Question

Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 15. g of ethane is mixed with 105. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

24h + 702 -> 400+ 6H₂O & H. Molarmass = 30g 1mol o molar mass=32 glmol Ho Molar mass = 18 glmol From equation moles a react with a moles Etc (78322gr o react with (2x 302gr Ç Ho 224 gr o react with Go go to 105 gr o react with a 105x60gr che mass of the required = 28.125gr But we have only 15gy site so She is Limiting reactant - 224 From equation 2 moles Çho produce 6 moles to (2x 302gr q he produce (6X 182go H₂O 60 gr its produce 108gr Ho 1588 che produce = 15 x108) gr Ho mass of tho= 2288