Write a program that receives a positive integer n from the user and then calculates the sum below by using a loop. Your program needs to ask the user to re-enter a different number if the user enters a non-positive one. Display the result. 1 SUM 1 2 3 ... n x x n = = = + + + +
Code:
#include<iostream>
using namespace std;
int main()
{
int n,i,sum=0;
cout<<"Enter a number to find the sum of numbers
below it:";
cin>>n;/*Reading number from the user*/
while(n<=0)
{/*This loop execute until user enter a positive
number*/
cout<<"Number should be
positive"<<endl;
cout<<"Enter a number to find
the sum of numbers below it:";
cin>>n;
}
for(i=1;i<=n;i++)
{/*This loop iterates for 1 to n*/
sum+=i;
/*Here we calculate the sum*/
}
cout<<"Sum is: "<<sum;
/*Finall we print the sum*/
}
Output:
indentation:
Write a program that receives a positive integer n from the user and then calculates the...
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