A spring-loaded toy gun is used to shoot a ball of mass m= 1.50kg straight up in the air, as shown in the figure. The spring has spring constant k=667 N/m. If thespring is compressed a distance of 25.0 centimeters from its equilibrium position y=0 and then released, the ball reaches a maximum height hmax(measuredfrom the equilibrium position of the spring). There is no air resistance, and the ball never touches the inside of the gun. Assume that all movement occurs in astraight line up and down along the y axis.
Find vm the muzzle velocity of the ball (i.e. the velocity of the ball at the spring's equilibrium position y=0).
Find the maximum height hmax of the ball.
Using the conservation of energy
Initial energy = final energy
(1/2)*k*x^2 = m*g*h
Given k = 667 N/m , x = .25 m , m = 1.5 kg
So ,
(1/2)*667*(0.25)^2 = 1.5*9.8*h
h = 0.5*667*0.25^2/1.5*9.8
h = 1.418 m
Now , to calculate hmax from equilibrium position
hmax = h - 0.25 = 1.418 - .25 = 1.168 m
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