Question

Question 27 5 pts How many grams of lithium fluoride, LiF (MW = 25.94 g/mol), are required for a 65.0 mL of a 0.725 MHF solut

0 0
Add a comment Improve this question Transcribed image text
Answer #1

det grams of di F required = ng Ka of HF = 7.2010 pka = -log (ka) 2 - log (7:2x104) - = 3.14 Using Henderson Hassebalch equilge Paga No pH = pka 1(25.94) (0725)/65 x 103 3.85 = 3.14 t log [ (2594110713/65 x103 J Solving above equation we get n = 6.23

Add a comment
Know the answer?
Add Answer to:
Question 27 5 pts How many grams of lithium fluoride, LiF (MW = 25.94 g/mol), are...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT