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11. The combustion analysis of 0.452 g of the hydrocarbon cubane (molecular mass, 104.16 g/mol) gives the following results:
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Answer #1

mol mol con= 1.528 1.528 yu 0.03472 mar ۔ 0.03472 ma o ho = 0.3126 1 - = 0.01so 0.01736 mol ] ۔۔۔۔ mol ha 0.0347 mi Divide al

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11. The combustion analysis of 0.452 g of the hydrocarbon cubane (molecular mass, 104.16 g/mol) gives...
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