Question

Review | Constants Coulombs law for the magnitude of the force F between two particles with charges and separated by a distance d is where K-L and印= 8.854 × 10 i2 C2/(N-m2) is the permittivity of free space Consider two point charges located on the x axis: one charge, g1--17.5 nC, is located at 1-1.705 m the second charge, g2 32.5 nC, is at the origin(z0.0000)

What is the net force exerted by these two charges on a third charge q3 = 46.0 nC placed between q1 and q2 at x3 = -1.235 m ?

Your answer may be positive or negative, depending on the direction of the force.

Force on q3

q3q_3

=
0 0
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Answer #1

Here, for the net force on the charge kept in between

Force = force due to -17.5 + force due to 32.5

Force = 9 *10^9 * 46 *10^-9 * 10^-9 * (-17.5/(1.705 - 1.235)^2 - 32.5/1.235^2)

Force = -4.16 *10^-5 N

the force acting on the middle charge is -4.16 *10-5 N

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