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1. What sample size is needed to estimate the mean white blood cell count (in cells per (1 poin microliter) for the population of adults in the United States? Assume that you want 99% confidence that the sample mean is within 0.2 of population mean. The population standard deviation is 2.5. O 601 1036 O 1037 O 33 2. The sample space of a population being researched contains 58 values and a mean of 318.6. (point The population has a known standard deviation of 29.2. Identify the margin of error for a 95% confidence interval estimate of the mean of the population 6.3072 7.5150 115.5608 O3.2064
le researching the cost of school lunches per week across the state, you use a sample size ( point) of 45 weekly lunch prices. The standard deviation is known to be 68 cents. In order to be 90% confident, what is the margin of error in units of dollars? 0.1987 89.7685 0.1668 0.0249 4. The number of DVDs in a random persons home collection is counted for a sample population (1 point) of 80 people. The mean of the sample is 52 movies; the entire population is known to have a standard deviation of 12 movies. Assuming a 99% confidence level, find the margin of error. 3.4547 2.6296 38.6536 59 4671
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Answer #1

1
sd = 2.5
alpha = 1% or 0.01
z(alpha/2) = 2.58

error = 0.2 = z(alpha/2) * sd/ sqrt(n)
sqrt(n) = 2.576 * 2.5/0.2
n = 32.2^2 = 1036.85

therefore, sample should be 1036 OPTION B

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