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11. The combustion analysis of 0.452 g of the hydrocarbon cubane (molecular mass, 104.16 g/mol) gives the following results:
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Hydrocarbon + 02 (excesi) G (O2 + H2O Amount of CO2 produced = Amount of H2o produced = 1.528 8 0.3126 g The moleular formulaVDULILLA (111) Divide each molar value by lowest value. C: 0.03475 9:0347ņa H: 0.0347 0.0347 © Thus, imbipercal formula = CH

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