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If 276 mL of a 2.30 M aqueous solution of Ca(NO3) is evaporated to dryness, what is the mass of the residue?
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Answer #1

volume = 216 ml = 2764 103 L A erity = 2.30 M. moles - Molacity & volume (2) - 2.3 x 276x103 - 634.8x10 moles. mass dis sampl

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If 276 mL of a 2.30 M aqueous solution of Ca(NO3) is evaporated to dryness, what...
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