6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was...
in a random sample of four microwave ovens, the mean repair cost was 65.00 and the standard deviation was 12.50 assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean u what is the margin of error of u? interpret the results In a Round to two decimal places as needed.)
In a random sample of 8 people, the mean commute time to work was 34.5 minutes and the standard deviation was 7.3 minutes. A 95% confidence interval using the t-distribution was calculated to be (28.4.40.6). After researching commute times to work, it was found that the population standard deviation is 9.4 minutes. Find the margin of error and construct a 95% confidence interval using the standard normal distribution with the appropriate calculations for a standard deviation that is known. Compare...
In a random sample of fivefive microwave ovens, the mean repair cost was $75.0075.00 and the standard deviation was $14.0014.00. Assume the population is normally distributed and use a t-distribution to construct a 9090% confidence interval for the population mean muμ. What is the margin of error of muμ? Interpret the results.
Question Help In a random sample of live microwave ovens, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use at distribution to construct a 90% confidence interval for the population mean . What is the margin of error of ? Interpret the results The 90% confidence interval for the population mean (Round to two decimal places as needed.) is C D Enter your answer in the edit fields and...
In a random sample of six microwave ovens, the mean repair cost was $65.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to construct a 90% confidence interval for the population mean mu. What is the margin of error of mu? Interpret the results. The 90% confidence interval for the population mean mu is ( nothing, nothing). (Round to two decimal places as needed.) The margin of error is nothing. (Round to...
In a random sample of six microwave? ovens, the mean repair cost was ?$90.00 and the standard deviation was ?$13.00 Assume the variable is normally distributed and use a? t-distribution to construct a 90?% confidence interval for the population mean ?. What is the margin of error of ???
In a random sample of 8 people, the mean commute time to work was 34.5 minutes and the standard deviation was 7.4 minutes. A 90% confidence interval using the t-distribution was calculated to be left parenthesis 29.5 comma 39.5 right parenthesis(29.5,39.5). After researching commute times to work, it was found that the population standard deviation is 9.3minutes. Find the margin of error and construct a 90% confidence interval using the standard normal distribution with the appropriate calculations for a standard...
6.2.17-T Question Help In a random sample of 21 people, the mean commute time to work was 34.9 minutes and the standard deviation was 7.3 minutes Assume the population is normaly distrbuted and use a t-distribution to construct a 80% confidence interval for the population mean μ what is the margin of error of μ? Interpret the results The confidence interval for the population mean μ is (Round to one decimal place as needed.) Enter your answer in the edit...
In a random sample of 18 people, the mean commute time to work was 33.8 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results.
In a random sample of 29 people, the mean commute time to work was 30.3 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results.