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In a random sample of fivefive microwave​ ovens, the mean repair cost was ​\$75.0075.00 and the standard deviation was ​\$14.0014.00. Assume the population is normally distributed and use a​ t-distribution to construct a 9090​% confidence interval for the population mean muμ. What is the margin of error of muμ​? Interpret the results.

• ### Question Help In a random sample of live microwave ovens, the mean repair cost was \$60.00... Question Help In a random sample of live microwave ovens, the mean repair cost was \$60.00 and the standard deviation was \$12.00. Assume the population is normally distributed and use at distribution to construct a 90% confidence interval for the population mean . What is the margin of error of ? Interpret the results The 90% confidence interval for the population mean (Round to two decimal places as needed.) is C D Enter your answer in the edit fields and...

• ### In a random sample of six microwave​ ovens, the mean repair cost was ​\$65.00 and the...

In a random sample of six microwave​ ovens, the mean repair cost was ​\$65.00 and the standard deviation was ​\$12.50. Assume the population is normally distributed and use a​ t-distribution to construct a 90​% confidence interval for the population mean mu. What is the margin of error of mu​? Interpret the results. The 90​% confidence interval for the population mean mu is ​( nothing​, nothing​). ​(Round to two decimal places as​ needed.) The margin of error is nothing. ​(Round to...

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In a random sample of six microwave? ovens, the mean repair cost was ?\$90.00 and the standard deviation was ?\$13.00 Assume the variable is normally distributed and use a? t-distribution to construct a 90?% confidence interval for the population mean ?. What is the margin of error of ???

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In a random sample of 8 people, the mean commute time to work was 34.5 minutes and the standard deviation was 7.4 minutes. A 90​% confidence interval using the​ t-distribution was calculated to be left parenthesis 29.5 comma 39.5 right parenthesis(29.5,39.5). After researching commute times to​ work, it was found that the population standard deviation is 9.3minutes. Find the margin of error and construct a 90​% confidence interval using the standard normal distribution with the appropriate calculations for a standard...

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In a random sample of 29 ​people, the mean commute time to work was 30.3 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 95​% confidence interval for the population mean μ. What is the margin of error of μ​? Interpret the results.