Question

3. Gaseous CH4 will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). Suppose 1.12 g of methane is mixed with 1.7 g of Oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits. CH4(g)+ 02 (g) ->_CO2(g) + H2O(g)

Answer 1

3 CHylg) + 20 (9) co219) + 2H₂0 (1) " Imol of Chy requires 2 mol of . mass of Chy - 1.129 molar mass = 16.0 g/mol . moles of CH4 = 1.12 mol = 0.070 mol mass of O₂ = 1.79 molar mass & 32.0 g/mol .: moles of O₂ = 1.7 mol Woles 1 160 32.0 = 0.051 mol which is less than twice the moles of CH4 & O2 is the limiting reagent. i moles of co2 produced a 1 x 0.051 mol molar mass = 44.0 g/mol mass of coa produced = txo.051844.0 g = [1,2 g 5 net ionic reaction (Ag coz should be solid instead of (aq) because it will precipitate 2 Ag+ (aq) + (aq) Ag, C03 (8)

Comment if any problem