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Part A Calculate the pH of the cathode compartment solution if the cell emf at 298...
1. Calculate the pH of the cathode compartment solution if the cell emf at 298 K...
1. Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.610 V when [Zn2+]= 0.20 M and PH2= 0.92 atm . Express your answer using two decimal places. pH= Switch 8.76 Voltmeter 7n anode NO, Na +H (8) Cathode compartment (standard hydrogen electrode) Anode compartment NO, Zn2+ NO NO, Zn(s) —> Zn2+ (aq)+ 2e 2H+ (aq) + 2e →H(8)
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is...
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when [Zn2+]= 0.40 M and PH2= 0.91 atm .
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is...
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.630 V when [Zn2+]= 0.26 M and PH2= 0.99 atm . Express your answer using two decimal places
Question 9 (1 point) In the following cell, A is a standard Zn2+1Zn electrode connected to...
Question 9 (1 point) In the following cell, A is a standard Zn2+1Zn electrode connected to a standard hydrogen electrode. If the voltmeter reading is -0.76 V, match each electrode with its correct name. Given: Standard reduction potential of the H+/H2 and Zn2+/Zn couples are 0.00 and -0.76 V, respectively. voltmeter saltbridg -Plis) H2 (g) Zn2+|Zn electrode 1. anode standard hydrogen electrode 2. cathode
A voltaic cell is made by placing a solid iron electrode in a compartment in which...
A voltaic cell is made by placing a solid iron electrode in a compartment in which the Fe2+ concentration is 2.0 x 10 -5 M and by placing a Pt electrode in the other compartment, in which the H+ concentration is 3.4 M and PH 2 = 0.700 atm. (This is a Hydrogen Electrode) What is emf (E) for the cell at the concentrations given? Fe(s) + 2H+(aq) --> Fe2+(aq) + H2(g) Hint, you do not have cell diagram, so...
Enter electrons as e A voltaic cell is constructed in which the anode is a Ni...
Enter electrons as e A voltaic cell is constructed in which the anode is a Ni Ni2+ half cell and the cathode is a Hg|Hg2+ half cell. The half-cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.) The anode reaction is: + + The cathode reaction is: + V> + The net cell reaction is:...
What is the effect on the emf of the cell shown in Figure 20.9, which has...
What is the effect on the emf of the cell shown in Figure 20.9, which has the overall reaction Zn(s)+2H+(aq)Zn(s) +2 H+(aq) −→−Zn2+(aq)+H2(g),→ Zn2+(aq) + H2(g), for each of the following changes? The pressure of the H2H2 gas is increased in the cathode half-cell. Zinc nitrate is added to the anode half-cell. Sodium hydroxide is added to the cathode half-cell, decreasing [H+].[H+]. The surface area of the anode is doubled. Can someone please explain why b is emf decreases? Why...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
a.) A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and...
a.) A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is a hydrogen electrode (P(H2) = 1 atm) immersed in a solution of unknown [H+]. If the cell potential is 0.204 V, what is the pH of the unknown solution at 298 K? b.) An electrochemical cell is constructed in which a Cr3+(1.00 M)|Cr(s) half-cell is connected to an H3O+(aq)|H2(1 atm) half-cell with unknown H3O+ concentration. The measured cell voltage is 0.366...
In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of...
In a test of a new reference electrode, a chemist constructs a
voltaic cell consisting of a Zn/Zn2+ half-cell and an
H2/H+ half-cell under the following
conditions: [Zn2+ ] = 0.021 M [H+ ]= 1.3 M
partial pressure of H2 = 0.32 atm. Calculate
Ecell at 298 K (enter to 3 decimal places).
Zn2+ (aq) + 2e −
⟶ Zn(s) E° = − 0.76 V
2H+ (aq) + 2e −
⟶ H2(g) E° = 0.00 V
We were unable...
Question 9 (1 point) In the following cell, A is a standard Zn2+1Zn electrode connected to a standard hydrogen electrode. If the voltmeter reading is -0.76 V, match each electrode with its correct name. Given: Standard reduction potential of the H+/H2 and Zn2+/Zn couples are 0.00 and -0.76 V, respectively. voltmeter saltbridg -Plis) H2 (g) Zn2+|Zn electrode 1. anode standard hydrogen electrode 2. cathode
Enter electrons as e A voltaic cell is constructed in which the anode is a Ni Ni2+ half cell and the cathode is a Hg|Hg2+ half cell. The half-cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.) The anode reaction is: + + The cathode reaction is: + V> + The net cell reaction is:...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
In a test of a new reference electrode, a chemist constructs a
voltaic cell consisting of a Zn/Zn2+ half-cell and an
H2/H+ half-cell under the following
conditions: [Zn2+ ] = 0.021 M [H+ ]= 1.3 M
partial pressure of H2 = 0.32 atm. Calculate
Ecell at 298 K (enter to 3 decimal places).
Zn2+ (aq) + 2e −
⟶ Zn(s) E° = − 0.76 V
2H+ (aq) + 2e −
⟶ H2(g) E° = 0.00 V
We were unable...
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