Question

A fish swimming In a horlzontal plane has velocity v, (4.00 i5.00 j) m/s at a polnt In the ocean where the positlon relatlve to a certain rock Is r(10.0 i 4.00 ) m. After the fish swlms wth contant acceleratlon for 16.0 s, its velocity is v (22.0i 5.00 j) m/s. (a) What are the components of the acceleration? ritt? (b) What is the direction of the acceleration with respect to unit vectori? (counterdlockwise from the x axis is positive) (c) If the fish maintains constant acceleration, where is it at t 21.0 s? TI In what direction is it moving? (counterclockwise from the +x-axis is positive)

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Answer #1

We know that

V= Vi+at

Where V=final velocity

Vi=initial velocity

a= constant acceleration

t= time

Let a=axi+ ay​​​​​​jandt-tone -t m/s 18 10 ms 1-125 m/sv ^^.. 9兰-29 , 05 o relative to x-ares clockwuse anis) 360° _ 29os. 330 95a positiow ate apply 2. 0349-0625 ー137-3125 J 31062-34 3125 , αχ, 331.0625 andy-36 8125 t 9rd feart: imal velreirz afer vel​​​​​​

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