Question

(I) Let's start with very simple data table 1.0 2.0 3.0 4.0 5.0 6.0 -1 ± 1.8 4±2.0 9+ 1.0 14 + 0.8 19 s 0.8 24 + 1.2 2% 1.8 34 ± 2.0 7.0 8.0 9.0 1. Plot a graph of y vs. X on a piece of graph paper 2. Is it a straight line? Draw the best-fit line. 3. Compute the slope and y-intercept for this line. Write the equation for y in terms of x using the straight line equation y mx+ b, where m is slope of the best-fit line and b is y-intercept 4. How is the b value calculated from the graph, and how is it calculated from the equation Gust saying that it is the "b" in the equation y -mx + b is not sufficient). Demonstrate this latter calculation.

Answer 1

Question 1.

Part (b) Above plot is straight line since data i fitted with equation y = m x + c, where m is slope of straight line and c is y-intercept of straight line. Part (c). From graph slop m = 5, and intercept c = -11. Part (d). m = b = 5 is slope of straight line. By hand it can be calculated using formula b = m = y_2 - y_1/x_2 - x_1 where (x_1, y_1) and (x_2, y_2) are any two points in graph.

Part (a). Plot is below

Part(b) Above plot is straight line since data i fitted with equation y = mx +c , where m is slope of straight line and c is y-intercept of straight line.

Part (c). From graph slop m= 5, and intercept c=-11.

Part (d). m= b= 5 is slope of straight line. By hand it can be calculated using formula

where (x₁,y₁) and (x₂,y₂) are any two points in graph.

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