A. When 1.591 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.378...
A. When 1.591 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.378 grams of CO2 and 1.101 grams of H2O were produced.
In a separate experiment, the molar mass of the compound was found to be 26.04 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
B. A 9.448 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 18.88 grams of CO2 and 7.729 grams of H2O are produced.
In a separate experiment, the molar mass is found to be 88.11 g/mol. Determine the empirical formula and the molecular formula of the organic compound.
Homework Answers
Add Answer to:
A. When 1.591 grams of a hydrocarbon, CxHy, were burned in a
combustion analysis apparatus, 5.378...
35a When 4.752 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.06...
35a When 4.752 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.06 grams of CO2 and 3.289 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 26.04 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. 35 part b A 4.079 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 9.273 grams of CO2 and...
1. When 2.689 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 8.437...
1. When 2.689 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 8.437 grams of CO2 and 3.454 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 56.11 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. 2. A 21.79 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21.31 grams of CO2 and 4.362 grams...
1) When 2.321 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 7.649...
1) When 2.321 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 7.649 grams of CO2 and 2.088 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 40.06 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Empirical formula= molecular formula= 2) When 2.201 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 7.442 grams of CO2 and 1.524 grams of...
When 3.741 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.65 grams...
When 3.741 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.65 grams of CO2 and 2.589 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 78.11g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
When 3.949 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.39 grams...
When 3.949 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.39 grams of CO2 and 5.073 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 56.11g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
When 3.061 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 9.603grams of...
When 3.061 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 9.603grams of CO2 and 3.932grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 42.08 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. What is the empirical formula? What is the molecular formula?
When 1.696 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.198 grams...
When 1.696 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.198 grams of CO2 and 2.483 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
When 1.860 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.699 grams...
When 1.860 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.699 grams of CO2 and 2.723 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
When 3.699 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 11.33 grams...
When 3.699 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 11.33 grams of CO2 and 5.414 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula =? molecular formula =?
1. When 1.389 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 4.771...
1. When 1.389 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 4.771 grams of CO2 and 0.7813 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 128.2 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
Most questions answered within 3 hours.
-
write a balanced chemical equation for the reaction
that occurs when aluminium metal undergoes a combination...
asked 4 minutes ago -
a
reduction in demand for kumquats could be caused by:
1 a rise in the price...
asked 17 minutes ago -
This code is not working while True: names = input("Enter input
string:") if names == "q":...
asked 14 minutes ago -
A car in the left lane of a highway is trying to pass a truck in...
asked 6 minutes ago -
A key reason that actively managed funds have lower returns than
index funds with a similar...
asked 15 minutes ago -
What is the freezing point of a solution that contains 22.5 g of
urea, CO(NH2)2, in...
asked 18 minutes ago -
10. Gas in a container is at a pressure of 2.0 atm and a volume
of...
asked 21 minutes ago -
A roulette wheel has 38 slots and a ball that rolls until it
falls into one...
asked 20 minutes ago -
why we use euler equation in fluid mechanics
asked 31 minutes ago -
2. Suppose that an urn contains: four $5 bills, three $50 bills,
and one $100 bill....
asked 37 minutes ago -
Scatterplots will show the nature and strength of the
relationship between X and Z. For this...
asked 38 minutes ago -
I need help with this please.
1. Calculate the volume of a 0.1M NaOH that 40.0...
asked 50 minutes ago