We would be looking at the first question here as:
From the standard normal tables, we have:
P(Z < 1.282) = 0.9
Therefore, due to symmetry, we get here:
P( -1.282 < Z < 1.282) = 0.8
The sample proportion here is computed as:
p = x/n = 75/221 = 0.3394
The 80% confidence interval for proportion here is computed as:
This is the required 80% confidence interval here.
Assume that a sample is used to estimate a population proportion p. Find the 80% confidence...
Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval for a sample of size 340 with 180 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. <p> Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 82 with 73 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p < Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 308 with 123 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p < Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 297 with 29% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. ___< p < ____ Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 289 with 254 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p < Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 144 with 34% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 99% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 299 with 88% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 99.5% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval for a sample of size 295 with 78% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 9090 C.1. = (0.778,0.782) 丼 Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 155 with 20 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 95% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval for a sample of size 276 with 221 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 90% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. can u show me the steps