Hardy-Weinberg
a. if you know allelic frequencies for a particular gene in your
class, can you calculate phenotypic frequencies. why or why not
b. if you know allelic frequencies for a population, can you always calculate phenotypic frequencies.
c. if the fraction of homozygous recessive in a population is known, can the allelic frequencies and genotypic frequencies always be calculated? what conditions must be met?
The Hardy-Weinberg law states that the proportions or frequencies of the alleles in gene pool of a population remain constant or at equilibrium from generation to generation unless acted upon by agents other than sexual recombination. The genotypic frequencies stabilize after one generation in proportions determined by allelic frequencies. The Hardy-Weinberg equation provides a standard to measure the changes in allele frequencies occurring in the natural populations without this equation the change in the frequency of alleles the magnitude and direction of the alleles and the forces responsible for change in allele characteristics can not be detected.
a) Yes. When allelic frequencies of a particular gene is known, the genotype frequency is known and the genotype frequency is relavant to the phenotypic frequency. For example, allele encoding Phenylthiocarbamide(PTC) results in bitter taste. Some people perceive the taste whiole others are not. The tasting ability depends on genotype of individuals. The individuals with genotype encoding two dominant alleles for PTC or heterozygous genotype with one dominant and one recessive results in individuals able to taste PTC. The individuals with two recessive alleles cannot taste PTC.
b) Yes. When allele frequency of a gene is known then the phenotypic frequencies can be calculated with help of genotype frequency.
c) When homozygous recessive fraction in a population is given, the frequency of recesive genotype and allele is calculated. The dominant allele frequency can be calculated using equation p= 1- q. For calculation of frequency of either of alleles, the conditions should meet include the population must be in equilibrium and frequencies of alleles should be equal to 1. The Hardy Weinberg equilibrium is determined with equation used to calculate allele frequencies and the equation is (p^{2}+2pq+q^{2} = 1).
Hardy-Weinberg a. if you know allelic frequencies for a particular gene in your class, can you...
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...
please click on the photo to see all of it The basic equations of Hardy-Weinberg Equilibrium p² + 2pq + q2 = 1 p+q=1 p= frequency of the dominant allele in the population 9 = frequency of the recessive allele in the population př= percentage of homozygous dominant individuals q* = percentage of homozygous recessive individuals 2pq - percentage of heterozygous individuals 1. You have sampled a population in which you know that the percentage of the homozygous recessive genotype...
Hardy Weinberg assignment P + Q = 1 In which P represents frequency of dominant allele and Q represents frequency of the recessive allele P2 + 2PQ + Q2 =1 P2 represents frequency of homozygous dominant 2PQ represents frequency of heterozygous Q2 represents frequency of homozygous recessive Consider a population of beetles on an island. There are 1000 beetles and they have different colored wings. Black wings are dominant over silver wings. Calculate the allele and the genotypic frequencies in...
Give the Hardy–Weinberg expected genotypic frequencies for an autosomal locus with three alleles, where the frequencies of alleles A1, A2, and A3 are defined as p, q, and r, respectively. Set the problem up and show your work. Tay–Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay–Sachs disease is 1 in 3600. If the Ashkenazi population is mating randomly for the Tay–Sachs gene, what proportion of the population consists of heterozygous carriers of the Tay–Sachs...
You are a population geneticist studying Gene B in a population that is in Hardy-Weinberg equilibrium. You sample a population to determine the genotypes at Gene B. You find that the freuency of homozygous recessive genotypes (bb) is 0.10. What would be the frequency of the dominant allele (B) in this population? A. 0.84 B. 0.4 C. 0.36 D. 0.6 E. 0.48
.1. The Hardy-Weinberg principle and its equations predict that frequencies of alleles and genotypes remain constant from generation to generation in populations that are not evolving. What five conditions does this prediction assume to be true about such a population? a._______ b._______ c._______ d._______ e._______ 2. Before beginning the activity, answer the following general Hardy-Weinberg problems for practice (assume that the population is at Hardy-Weinberg equilibrium).a. If the frequency of a recessive allele is 0.3, what is the frequency of the dominant...
reting Data: Hardy-Weinberg Equation 2 of 10 you use the Hardy Weinberg equation to answer questions about a hypotheticalcat population Part A A hypothetical population of 500 cats has two wees, Tandt for a gene that codes for tail length (Tis completely dominantot) The table below presents the phenotype of cats with each possible genotype, as well as the number of individuals in the population with each genotype. Assume that this population is in Hardy-Weinberg equilibrium Recall that the Hardy...
Use the Hardy-Weinberg equations (p2 + 2pq + q2 = 1 and p + q = 1) to find the genotypes of the following hypothetical phenotypic information: a. Within a particular population, you observe that 450 individuals have freckles (dominant, F) and 550 do not have freckles (recessive, f). b. Homozygous dominant (frequency) ______(A)_________ c. Heterozygous (frequency) ______(B)_____________ d. Homozygous recessive (frequency) _______(C)____________
2. Hardy-Weinberg Equilibrium; chi-square test Sickle cell anemia is a recessive disorder caused by a recessive mutation (S) in the b-hemoglobin gene. 80% of affected SS individuals die before reproducing. Heterozygotes (AS) and homozygous dominant (AA) individuals do not have sickle cell anemia. The table below shows the number of people of each genotype in a population of 100 people in population of Cameroon. Observed # individuals in a Cameroon population AA AS SS 62 32 6 What are the...
EXERCISE 6 HARDY-WEINBERG EQUILIBRIUM Work in a small group or alone to complete this exercise. In human population X consider the simple Mendelian trait for freckles. F is the dominant allele and fis the recessive allele. Individuals who are homozygous dominant (FF) or heterozygous (F) for the trait express freckles. Individuals who are homozygous recessive (ff) for the trait do not express freckles. In this population, 30% (0.3) of the alleles are recessive (1) and 70% (0.7) are dominant (F)....