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6. Insurance companies track life expectancy information to assist in determining the cost of life insurance policies. They w
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Here we have: X = 78.6 S= 5.12 n = 20 a = 1-0.95 = 0.05 (95% confidence level) df = n-1 = 20- 1 = 19 Critical value: tcrit= t

= 78.6 + 2.093 * 5,22 = 78.6 + 2.396 = 76.204 <u <80.996 We are 95% confident that the population mean of life expectancy is

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