Question

Consider the partially completed one-way ANOVA summary table below. a) Complete the remaining entries in the table. b) How many population means are being tested? c) Using a = 0.05, what conclusions can be made concerning the population means? Sum of Squares Degrees of Freedom Mean Sum of Squares w Source Between Within Total Click the icon to view a table of critical F-scores for a = 0.05. a) Complete the ANOVA table below. Sum of Degrees of Mean Sum of Source Squares Freedom Squares Between Within 48 Total 69 (Type integers or decimals. Round to three decimal places as needed.) b) There are population means being tested. c) What are the hypotheses for this test? O A. Ho: All the means are equal. Hi: None of the means are equal. OB. Ho: Not all the means are equal. Hi: All the means are equal. O C. Ho: All the means are equal. Hi: Not all the means are equal. OD. Ho: None of the means are equal. Hj: All the means are equal. Determine the critical F-score, Fæ, for this test.

Answer 1

This is the example of ANOVA one way table, we shall complete the table as given below calculate tye result as
The 1 given source docta is given by 1 Sum of squares I Dafo I Mean Sum of Square Between Set within Total I 48 1 69 - 1 197 Here Total rum of square 68 Sum of square of Erros (within) = 49 So, sum of square of theatment got = 69-48=21 As dos. of Treatment or between = 3 -) 64 = 3 p=4 Total difo = 19 i. Dof. of sum of square of within = 19-3=16 So, the Mean Sum of square of between or treatment = MST = 2 =7 So, the mean Sum of square within osoithin = 48 = 3 = MSE the So, the f Stectistics = MST = 7 = 20 333 чne 7 Critical value o Esteetistics at se significance with out. (3, 16) is 3.24. Since the critical value is greater than calculated valve to calculated vabe is less then tabulated valve, we may accept hull hy botheris.

(a) the final table is I s Source Between 1 o.s. I Mean sum of 7 3 7 Solove sum of Square 21 = 2.333 within 48 Total 69 1 91 1o (6) Nul ng bothesis Moi M=M2 = 143 = My ke. All the means are equal : Alternate Hypother's Hi: M & M & fez try lepo to the means are equal. There are 4 lobulation mears is testell. red since the cortical Fasole = 3.24 So, the f-test statistic is less than the chritical f-sore we may accelst the hell hybothent and conclude that all of the lobulation mean are equal.