Question

For the following multistage amplifier, find V2 if Vo=40 V, V1=0.2 V, R1=12.0 K2, R2=9.0 KQ, R3=1.0 K, R4=1.0 K2, R5=9.0 K and RL=16.8 K. R5 R1 + R4 Vo 14 V1 R2 RL + V2 no R3 Answer: OV Consider the same circuit as above, but with the following parameters: if Vo=40 V, V1=0.2 V, V2=0.5V, R1=7.3 K2, R2=11.9 K2, R3=1.0 K, R4=0.8 K2, R5=10 K2 and RL=17 K2. What is the magnitude of the current 14 through resistor R4?

Answer 1

ON RS Ve Ru R. TA R2 R3 V2 = ? Rs = 9.0t2 Ri=12KR VA Ry=look2 i6 А t vo 40 R₂ = 16.8K2 Ji2 TV=0.9v R2=980 سے R3=122 din A point voltage VA i, sizzo ( Scleal o pamp) Apply virtual short circuit concept At point B VB=0.21 Apply KCL At nado at pant B 13 = iy VA-0.2 TK 0.2 aku 0.289 VA-0.2 - VA $ 1.6to.2 VA 2.0V var WS SCTS

Apply viatual circund et node C Vz at node Now Apply KCU is = io Varive Vc -vo Tota 1.ok 2 9 - 40 9 2 V₂-40 ។ 14-902 = Vz-yo 18tyo = love Vz= V₂ c 5.6V

Vo = MOV, - consider the same cirail ab a boue lut cinth the Collowly perasvenes il 0.2 = 0.56 R = 7.3kn, R2 - 11.9kn Rz: lotur I Ryo.8K2, Rs = lots and Ri=1?k!. What is the magnilude of the currat 14 through Resistor R4? RS loksa R, 27.362 -) is VA Ru=oed12 -0.2 V 0.5 V J4 + PR2 R = 11.962 v2 =o.su VB viz 'R.3=1.0km CS Scanned orth CamScanner

currat across laud ie= vo Ri ub AL no 17KU 2.35mA i5 o.svo R5 (6.5=40) 39.5 is = 3.95 mA at node c Apply KCL in is -3.15A - VA in -3.95 MA