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Albinism (lack of skin pigmentation) is caused by a recessive mutation on one of the autosomal chromosomes. A man and woman,
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Albinism is the lack of skin pigment. And it is autosomal recessive trait .

Let assume A gene is normal and mutated a gene is responsible for albinism. As albinism is a recessive trait, hence both the gene would be mutated i.e only homozygous aa genotype can express the trait .

Here, man and woman ( parents) both have phenotypically normal skin . But their child is albino .

Therefore the child's genotype is homozygous recessive ( aa ) ( 2nd option is right)

[ because only homozygous aa genotype can express the trait. And for this both the parent must pass one mutated a gene. So both the parent's genotype is heterozygous Aa . ( A is dominant over a so person with heterozygous Aa genotype can not express albinism. they will be phenotypically normal and will act as carrier .

Phenotypically normal but carrier father (Aa) × phenotypically normal but carrier mother (Aa)

A ( father's gamet) a ( father's gamet)
A (mother's gamet) AA Aa
a (mother's gamet) Aa aa (albino child )

1st option is wrong as albinism is recessive trait.

3rd option is also wrong because heterozygous condition (Aa) can not express albinism.

4th option is also wrong because hemizygous conditions is seen in case of sex linked trait ( male carries single X Chromosome hence known as hemizygous) and albinism is autosomal.  

5th option is also wrong as information is enough and child 's genotype is homozygous aa ( recessive trait)

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