sample mean, xbar = 60
sample standard deviation, s = 14
sample size, n = 4
degrees of freedom, df = n - 1 = 3
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, tc = t(α/2, df) = 2.353
CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (60 - 2.353 * 14/sqrt(4) , 60 + 2.353 * 14/sqrt(4))
CI = (43.53 , 76.47)
ME = tc * s/sqrt(n)
ME = 2.353 * 14/sqrt(4)
ME = 16.47
Margin of error is 16.47
OPtion A) is interpretation
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