Question

The emfs in the figure below are &z = 5.00 V and E2 = 21.0 V. The resistances are R1 = 18.0 , R2 = 32.00, R3 = 45.5 2, and R4 = 59.0 9. Find the magnitude of the current in each resistor when the switch is in the following states. R2 R4 R S R3 (a) open 11 = X Enter a number. differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. A A 12 = 13 = 14 = A A A (b) closed 11 = 12 = 13 = 14 = A A А

Answer 1

E, - 5 V, E2 = 21 V R2 Ri=1812 R = 322 Ry Е, R₂ =45:58 it f S E, R3 R-5912 9 (a) switch is open Then no Ru current will flow through resistor. 1.0, =0 Apply Kirchott's voltage the loop: C R2 R ş law in M R3 - Ez+iRz+iR, IR, 20 E2 2) ia R, +R, fR3 18+3274505 0.2198 A I Oo 2198 - 02198 А is Iz = 0.21.98 A A T .4

b switch is closed: Rr 1.3 23 loop-1 R. A loop-2) Er iq + ده E 23 R. Apply kirchott's voleage law in both loops: loop-1. VR4-6, till, = 0 ", Ritluly = € 18, +5914-5->0 loop-2 ; -Ezt 23 R₂ + Rt i R=0 23 ir t 43 (R₂ + R₂ ) = Ez 181, + 14 (32+45-8)= 21 181, + 7705=21 it ng But; i = zz tiu 28-i-ina i

18, 67705 (i, (y)=21 189, +7osi - Trogly = 21 quosi, -77: 514 = 21 → (2 OX 745 ) 18x Trosi +59xatosiu = 587.705 Ⓡx 59 z) 9535839.i; - 5967705 = 21859 Add 7029.5. i = 1626=5 А =0 0-23.1 substitute in O S-18 5-18 x 0.23) 19 iy 59 59 А 11 ODIU { 2 = 1; -4 = 0.231–6.441 = 0.217. A 23 OĆ 231 A G - 0217 Iz A 0 217 A Iz = 0.014 A Iy