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Calculate the heat required in Joules to convert 18.0 grams of water ice at a temperature...

Calculate the heat required in Joules to convert 18.0 grams of water ice at a temperature of -20° C to liquid water at the normal boiling point of water.
Given:
-specific heat of ice = 2.09 J/g°C
-specific heat of liquid water = 4.184 J/g°C
-specific heat of water vapor = 2.03 J/g°C
-molar heat of fusion of water = 6.02 kJ/mol
-molar heat of vaporization of water = 40.7 kJ/mol

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Answer #1

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