Question

QUESTION 1:

A spaceship traveling east flies directly over the head of an inertial observer who is at rest on the earth's surface. The speed of the space ship can be found from this relationship: sqrt(1 - (v^2/c^2) = 1/2

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SHOW all CALCULATIONS and FORMULAS, for full credit to be received (Parts (a) through (e)

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(a) The observer is 5 feet all. According to the navigator of the space ship, how tall is the observer? [Answer 5 ft]

(b)The navigator of the space ship observes a neon sign on a storefront. If he measures th speed of light emitted from the sign as he approaches the sign, what value will he obtain?

(c) The navigator's on-board instruments indicate that the length of the space ship is 20 m. If the
length of the ship is measured by the inertial earth-bound observer, what value will be obtained? [Answer: 10 m]

(d) The pilot fires an ion gun that propels ions from the space ship at 1.0 × 108 m/s relative to the ship.
What is the speed of the ions as measured by the earth observer? [Answer 2.8 × 108 m/s]

(e) An apple falls from a tree and takes 4 s to reach the ground as reported by the earth-bound
observer. According to the navigator's instruments, how long did it take the apple to fall? {Answer: 8 s]

Answer 1

to 1 1- 2 since, 2= 11 And to 4s (given ) Then, t = T = 8 s Ans. 2
last one is (e) not (d). this is typed by mistake. Sorry for that.