Question

Ashbrook Golf Course wants to estimate the mean time for a round of golf for all golfers at their course. They wish to estima

0 0
Add a comment Improve this question Transcribed image text
Answer #1

To get 95% confidence distrutution table le this standard Z=1.604 u= 185 os 6 = 11:15 - 11.15 Z=24 x=26+ u a = 1604 (11-15) +

Add a comment
Know the answer?
Add Answer to:
Ashbrook Golf Course wants to estimate the mean time for a round of golf for all...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The owner of a golf course wants to determine if his golf course is more difficult...

    The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 27 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 27 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on...

  • Nielsen Media Research wants to estimate the mean amount of time ( in minutes) that full-time...

    Nielsen Media Research wants to estimate the mean amount of time ( in minutes) that full-time college students spend watching television each weekday. Find the sample size necessary to estimate that mean with a 15-minute margin of error. Assume that a 96 % confidence level is desired. Also assume that a pilot study showed that the standard deviation is estimated to be 112.2 min.

  • Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza...

    Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza from the local pizza parlor. Over the course of a few months, the customer orders 29 pizzas and records the delivery times. The average delivery time is 23.69 with a standard deviation of 7.212. If the customer estimates the time using a 95% confidence interval, what is the margin of error? Question 1 options: 1) 0.7137 2) 2.2782 3) 2.7433 4) 1.3392 5) 2.739...

  • Question 7 (1 point) The owner of a local golf course wants to determine the average...

    Question 7 (1 point) The owner of a local golf course wants to determine the average age of the golfers that play on the course in relation to the average age in the area. According to the most recent census, the town has an average age of 55.89. In a random sample of 30 golfers that visited his course, the sample mean was 45.84 and the standard deviation was 6.514. Using this information, the owner calculated the confidence interval of...

  • A store manager wants to estimate the mean number of customers to survey to know their...

    A store manager wants to estimate the mean number of customers to survey to know their satisfaction level about their shopping experience. The estimated margin of error is desired to be 1 with a 95% level of confidence. A pilot study provided a standard deviation of 2. How many customers should be sampled?

  • (10 pts) Use the following information for all parts: On a particular golf course, a sample...

    (10 pts) Use the following information for all parts: On a particular golf course, a sample of 40 golfers have a mean golf score of 79. Suppose the population standard deviation for this course is 3.6605. (a) Using the formula a 90% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter where x is any number, type sqrt(x). For example, should be typed as...

  • 1.The owner of a golf course wants to determine if his golf course is more difficult...

    1.The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 8 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 8 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on...

  • In developing patient appointment schedules, a medical center wants to estimate the mean time that a...

    In developing patient appointment schedules, a medical center wants to estimate the mean time that a staff member spends with each patient. How large a sample should be taken if the desired margin of error is two minutes at a 95% level of confidence? How large a sample should be taken for a 99% level of confidence? Use a planning value for the population standard deviation of 6 minutes. 95% Confidence (to the nearest whole number): 99% Confidence (to the...

  • (1 point) Use the following information for all parts of this problem. On a particular golf...

    (1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72. Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places). 81.61 to 84.39 Part 3: Calculate the margin...

  • Managers believe that the average time to process a package at the front of the counter...

    Managers believe that the average time to process a package at the front of the counter of the Mercuric post office is about three minutes. They want to do a work sampling study to estimate this time more accurately. From a small pilot sample, the standard deviation is estimated to be 0.16 minutes. Management wants to find the sample size needed to achieve a maximum allowable sampling error of ±0.025 minutes with 95 percent confidence. Note: Answer in two decimal...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT