Question

(d) Test the observed frequencies ved frequencies against the expected frequencies using a goodness-of-fit ainst the expected freque test. The relevant critical value is x2 = 5.991. Show your work. e) Do these results support or contradict your prediction from question (a)? Explain in detail. 8. Most domestic cats (Felis cattus) are well-known junkies of catnip, Nepeta cataria. However, not all are. Some just ignore it. It turns out that other cat species, including leopards (Panthera pardis), respond to catnip like house cats do some are fools for the stuff and others ignore it. This response is inherited as a relatively simple dominant Mendelian trait. In one study (this is true), researchers found that 14 of 18 leopards responded to catnip (had the dominant trait). Given these data, what is the best estimate of the frequency of wild leopards who are heterozygous for the catnip response, assuming the trait is in Hardy- Weinberg equilibrium?

Answer 1

Let,

p= frequency of dominant allele

q= frequency of recessive allele

p² = frequency of homozygous dominant individuals

2pq= frequency of heterozygous individuals

q² = frequency of homozygous individuals

Accroding to Hardy-Weinberg,

p+q=1; p² +2pq+q² = 1.

Here response to catnip is a dominant trait.14 out of 18 lepards responded to catnip.

p² = 14/18= 0.78 , p= √0.78= 0.88

q=1- p= 1-0.88=0.12

2pq= 2x0.88x0.2= 0.21

So the frequency of wild lepards who are heterozygous for the catnip response= 0.21.