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In humans, sickle-cell anemia (HBBSHBBS) is caused by the recessive condition of an autosomal gene with...

In humans, sickle-cell anemia (HBBSHBBS) is caused by the recessive condition of an autosomal gene with two alleles: HBBA (wild-type) and HBBS (sickle-cell mutation). In one population, the frequency of individuals who do not suffer from sickle-cell anemia (HBBAHBBA and HBBAHBBS) is 0.9964. Assuming the population is in Hardy-Weinberg equilibrium, what is the frequency of the HBBS allele?

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Answer #1

p(HBBA)=a

p(HBBS)=b

p(HBBAHBBA)=a2

p(HBBSHBBS)=b2

p(HBBAHBBS)=2ab

Accordin to Hardy-weinberg principle

a2 +2ab+b2=1

so, b2=1-.9964

b=p(HBBS)=0.06

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