In humans, normal pigmentation is dominant to albinism; and wet earwax is dominant to dry earwax. A man that is heterozygous for both traits marries a woman that is also heterozygous for both traits. What would be the phenotypic ratio of the offspring?
Notations used :
A : Normal pigmentation
a : Albinism
B : Wet Earwax
b : Dry Earwax
Since A is dominant over a , and B is dominant over b, so -
Genotype of Heterozygous Man = AaBb
Genotype of Heterozygous Woman = AaBb
Gametes from Man = AB , Ab , aB and ab
Gametes from Woman = AB , Ab , aB and ab
This punnett square will depict that their crossover will yield :
The Phenotype of Offsprings will be :
Normal Pigmentation + Wet Earwax = 9 ( AABB, AABb, AaBB, AaBb, AABb, AABb, AaBB, AaBb, AaBb)
Normal Pigmentation + Dry Earwax = 3 (AAbb, Aabb, Aabb)
Albinism + Wet Earwax = 3 (aaBB, aaBb, aaBb)
Albinism + Dry Earwax = 1 (aabb)
So the phenotypic ratio will be 9 : 3 : 3 : 1 respectively, for this dihybrid cross.
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