1) If a culture has an instantaneous growth rate constant of 0.00090832 min-1, what is the...
1) If a culture has an instantaneous growth rate constant of 0.00090832 min-1, what is the doubling time of the culture?
- Express your answer in minutes using exponential notation.
- 48.2 minutes would be 4.82E1
- Round your answer to two decimal places
- 32.67 minutes would be 3.27E1
2)Given a doubling time of 635 minutes, how long will it take a culture to grow from 14 cells per mL, to 47,621 cells per mL?
- Report your answer in minutes, rounded to 2 decimal places.
- Do not use exponential notation.
Homework Answers
Answer 1:)
Calculate the doubling time by use the following formula:
Td = 70/r
Td is the doubling time, and r is the growth rate.
Given that r = 0.00090832 min-1
Td = 70/0.00090832
Td = 77065.35
Td = 7.7E4 mins
Answer 2:)
To calculate the time of the growth of a culture, use the following formula:
Nt = N02t/Td
Nt = number of cells (t time).
N0 is the initial number of cells.
Given that,
Nt = 47,621 cells per mL
N0 = 14 cells per mL
Td = 635 minutes
47621 = 14 x 2t/635
2t/635 = 3401.5
Taking log on both sides
Log 2t/635 = log 3401.5
t/635 x log2 = 3.53
t/635 x 0.3 = 3.53
t = (3.53/0.3) x 635
t = 0.00167 minutes
t = 1.67 x 10 -3 minutes
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