Question
in a random sample of four microwave ovens, the mean repair cost was 65.00 and the standard deviation was 12.50 assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean u what is the margin of error of u? interpret the results Sample size n = 4

Degrees of freedom = n-1= 3

The critical value of t for 3 df with 95% Confidence is +/-3.182

The 95% Confidence Interval for is  The 95% Confidence Interval for is ( 45.11, 84.89)

b) The Margin of Error is c) Interpretation : Option B) If a large sample of microwave are takken approximately 95% of them will have repair costs between the bounds of the confidence interval.

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