We will use the Hardy Weinberg assumption were:
p = Dominant allele
q = Recessive allele
p + q = 1
p2 = frequency of homozygous dominant
q2 = frequency of homozygous recessive
2pq = frequency of heterozygous
Recessive frequency of recessive genotype = 1% = 0.01
Calculate the frequency of the recessive allele (q) = √0.010= 0.1
Calculate the frequency of the dominant allele
p = 1-q = 0.9
Calculate the frequency of homozygous dominant (p2)
p2 = 0.92 = 0.81
Calculate the frequency of heterozygous
2pq = 2 x 0.01 x 0.81 = 0.162
Now, to determine the number of each genotype in the population, multiply each frequency by the total number of the population (1000)
Number of recessive individuals = 1000x0.01 = 10
Number of homozygous dominant individuals = 1000 x 0.81= 810
Number of heterozygous individuals = 810 – 10 =180
The correct answer is 810 W/W, 180 W/w, 10 w/w
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