the earth’s magnetic field is about 50 µT, at a 60° dip angle. If your textbook is resting on the table, what is the downward flux through the cover of the book?
Vertical component of earth's magnetic.field
So
Flux via cover (let A =area of cover)
the earth’s magnetic field is about 50 µT, at a 60° dip angle. If your textbook...
Based on your measured values of dip angle (64°) and , compute the 3 dimensional magnitude of the earth’s magnetic field. Show your work, including a sketch showing how relates to and dip angle and what equations were used to solve for . Beh Beh B We were unable to transcribe this image Beh Beh B
At the equator, the earth’s field is essentially horizontal; near the north pole, it is nearly vertical. In between, the angle varies. As you move farther north, the dip angle, the angle of the earth’s field below horizontal, steadily increases. Green turtles seem to use this dip angle to determine their latitude. Suppose you are a researcher wanting to test this idea. You have gathered green turtle hatchlings from a beach where the magnetic field strength is 50 μT and...
Review Part A A magnetic field is oriented at an angle of 50 ° to the normal of a rectangular area 5.6 cm by 7.7 cm If the magnetic flux through this surface has a magnitude of 4.9x10-5T-m2 , what is the strength of the magnetic field? Express your answer using two significant figures. B-22 mT Submit X Incorrect; Try Again; 3 attempts remaining
A uniform magnetic field passes through a horizontal circular wire loop at an angle 60° from the normal to plane of the loop. The magnitude of the magnetic field is 3.0 T, and the radius of the wire loop is 10 cm. Find the magnetic flux through the loop.
A 10cm×10cm square is bent at a 90∘ angle. A uniform 7.00×10−2 T magnetic field points downward at a 45∘ angle.(Figure 1) What is the magnetic flux through the loop? 5 em 10 cm 45f 5 cm
A proton in the Solar wind strikes the Earth’s magnetic field at a right angle with a velocity of 2.75 x 105m/s. If the field has strength of 4.33 x 10-5T and the Lorentz force acts to move the proton in a circle, what’s the radius of this circle? A) 0.0589m B) 6.08 x 1019m C) 2.64 x 10-10m D) 66.3m
*It is a west-facing room Magnetic Flux: 1, Earth's magnetic field in the room has magnitude 52.5μΤ and lies in a north-south plane but points downward at an angle of 65.0° relative to horizontal. Determine the magnetic flux through each surface of a 3mx3m room with a roof angled at 30° relative to horizontal (the low wall has a height of 3m). Magnetic Flux: 1, Earth's magnetic field in the room has magnitude 52.5μΤ and lies in a north-south plane...
A magnetic field is oriented at an angle of 46 ∘ to the normal of a rectangular area 4.8 cm by 6.0 cm. If the magnetic flux through this surface has a magnitude of 5.0×10−5 T⋅m2 , what is the strength of the magnetic field (mT)?
Assume the average value of the vertical component of Earth's magnetic field is 50 μT (downward) over an area of 3.10 ✕ 105 km2. What then are the magnitude and direction (inward or outward) of the net magnetic flux through the rest of Earth's surface (the entire surface excluding this area)?
#2 near the ground at the north magnetic pole, the earth’s magnetic field is directed downward vertically and has a strength of 0.57 G. An electron at the north pole is projected from the ground into this magnetic field with a velocity of 1.4 km/s vertically upward and 1.9 km/s horizontally to your right. A) find the magnitude of the force acting on this electron B) find the electron’s acceleration (magnitude and direction)