An electric point charge of Q1 = 6.25 nC is placed at the origin of the...

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Answer 1

Answer #1

X 2-37 (2.37 -а

Electric force on charge 'q' by charge Q₁ is given as

F₁ = k Q₁ q / AB² = (9 x 10⁹) (6.25 x 10^-9) (5.33 x 10^-9) / a² towards left eq-1

Electric force on charge 'q' by charge Q₂ is given as

F₂ = k Q₂ q / BC² = (9 x 10⁹) (4.55 x 10^-9) (5.33 x 10^-9) / (2.37 - a)² towards right eq-2

For Net force to be 0 ,

F₁ = F₂

(9 x 10⁹) (6.25 x 10^-9) (5.33 x 10^-9) / a² = (9 x 10⁹) (4.55 x 10^-9) (5.33 x 10^-9) / (2.37 - a)²

(6.25 x 10^-9) / a² = (4.55 x 10^-9) / (2.37 - a)²

a = 1.279 m

Answer 2

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