Question

6. The allele for curly hair is codominant to the allele for straight hair, the heterozygote has wavy hair. if two people with wavy hair marry, what hair types would you expect among their offspring 7. Two children in a family have blood type. The mother has type B, and the father has type A a. What are the genotypes of all of the individuals? b. What is the probability that their next child will have blood type O? 8. In humans, normal pigmentation is due to the dominant allele of a gene, albinism is due to the recessive allele. A normal man marries an albino woman. Their first child is albino. a. What is the genotype of the father? b. What is the probability that the next child will be an albino? C. Would it be possible for two albino people to have a child with normal pigmentation?

Answer 1

Codominant is a phenomenon where one allele cannot supress the other one hence both of the expression of the allele are present in the offspring.

In human A blood type is determined by a dominant allele IÅ . If both the allele are present or if atleast one allele is present it will cause a blood type. Like A blood type B blood type has caused by the present of atleast IB allele. If both are present or atleast one present it will give B blood type. O blood type is caused a recessive allele "i". To develop o blood type both "i" allele nust be present.

In complete dominant, one dominant allele completely supress the expression of the recessive one. To have a normal pigment one dominant allele is enough but to have albino present of two recessive allele must be required.

COH 611 HAND The allere for Cusly hair is co dominans to allele for straight hair. co dominant is refered to Phenomenon where one allele cann of completely suppress the front of another allele and a new character is Produced. Here the wavy hair is the new charecter where both the corey and straight hair Present. - DATA 0 Suppose the allele responsible for Corty hair is T and is Straight hair is to Here 't is codominant to f'. cussy hair x straight heures C TT X tt Herero zygous - TC A to warry heres. here the cusey heu'r cannone dominant the expression of straight hair, hence a new Chanecten arises. Now meeting two warry hauts, AYD

0 00 2100 4 DOT VODE TTTTTT tTt tt 1 curly hair (TT) here. Over 1 offspring will have 2. W in uslubino wavy hair (Tt). i eluolu o straight hais (H). Here wavy hair will hair means both woy and straight- present in different patches. 71 Ua au Two children have mood group or o blood group is caused by present to roo homozygous recessive allele il 9 bool! The money has a type blood group. "A blood group is caused by the presence of "It allele. . If Both on Bor Born the allele one I Å then It will produce 'A blood type. one I If Å and one i is allele presene then ai will auso produce P A blood type. - Because IA is dominant to e

Now farmer has a blood type. sike A blood type "B" mood type is produced by Presence of two IB allere at present of one IB alele and one ? auell. (9) IB is dominant to le Hence both two children has o blood type I then the genotype of mother and father must be IA i and IB i respectively. As the penotype of ou brood bype is al both mothes and father must have one & allele, Тех hox I8 22222 (140 by to 0 old bool D I B vo b o r 2 duos TAIB TAI li Bi So I o' blood type children for 4 children 1 will be 'o' blood type 2. 8 2 4 12 naar zouao u blood go the probability of having third child with type is 3/12600 - 25%.

811 . Normal pigmentation is dece to dominant allele on con is due to recessive allele. Albino to assume The allele responsible for ato Normey Pigmentation is A and for albino is a I so we can say Å is dominant to I disa grouw i orroio ao morbind 04. W oo do 8 isin ixou Now a normay men genorype AA aulo Albino women genotype af aan These Next If we cross w it then we will get AA x aa A @ It will be normal people. because Å allere supress the expes Com) a abula. child which genotype. Is ☺ W But they a albino child which neue a au

so here If we cross a hererozygous Normal with a Albino woman. a Aa Jaa lo a Aaaa Children ane albino - look here crenotype aa) (a) so the father must be a herenzygous Normal who have one recessive allele. hence genotype - Aan so the from Punner square we see that out of 4 children, 3 are albino so the probability to have next albino child is 3/4X100 = 45%. I orfall look Normas Pigmentation is dominanero Albino. Hence to became a normey Pigment People at least one copy of dominant allele 'A ' is need,

person will have the genotype But two albino of "aa" aa x aa - here all will be cel bino a laalaa a aaaa so it is not I to have a child possible for two albino Person with Normal Pigmentation.