Individual homozygous dominant for a population at 16 percent recessive would make up
p2 + 2pq + q2 = 1
p + q = 1
0.16 + q = 1
q = 1- 0.16
= 0.84 i.e 84 % (dominant)
2 p x q
2 x 0.16 x 0.84 = 0.2688 i.e ( c ) 24% approx
3. Diamptomous priminas frequency with short antenna:
(0.09) (a)
If individuals homozygous for a recessive mutation make up 16% of a population at Hardy-Weinberg equilibrium,...
In a population that meets Hardy- Weinberg equilibrium assumptions, 81% of the individuals are homozygous for the recessive allele. What percentage of the individuals would be expected to be heterozygous for this locus in the next generation?
In a population that is in Hardy Weinberg equilibrium, 49% of the individuals are recessive homozygotes for a certain trait. In a population of 5500, calculate the following: a) The number of homozygous recessive individuals in the population b) The number of heterozygotes in the population
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