How molecules of CO2 (g) are produced when 0.75 moles of propane are burned? Chemical reaction: C3H8 + 5O2 à 3CO2 + 4H2O
moles C3H8 consumed = 0.75 mol
moles CO2 produced = (moles C3H8 consumed) * (mole ratio of CO2 to C3H8)
moles CO2 produced = (0.75 mol) * (3 mol CO2 / 1 mol C3H8)
moles CO2 produced = (0.75 mol) * (3)
moles CO2 produced = 2.25 mol
molecules CO2 produced = (moles CO2 produced) * (Avogadro's number)
molecules CO2 produced = (2.25 mol) * (6.022 x 1023 molecules/mol)
molecules CO2 produced = 1.355 x 1024 molecules
molecules CO2 produced = 1.4 x 1024 molecules (correct number of significant figures)
How molecules of CO2 (g) are produced when 0.75 moles of propane are burned? Chemical reaction:...
27) When propane (C3H8) reacts with oxygen, carbon dioxide and water are produced. The balanced equation for this reaction is: C3H8 (g) + 5O2 (g) ---> 3CO2 (g) + 4H2O (g) Suppose 17.8 moles of oxygen react. The reaction consumes ___ moles of propane (C3H8). The reaction produces ___ moles of carbon dioxide and ___ moles of water. How many grams of water are produced in the complete reaction of 27.2 grams of propane (C3H8)? ___ grams
The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 7.5 mol of O2 with 1.4 mol of C3H8 will produce ________ mol of CO2. Group of answer choices.
The balanced chemical equation for the combustion of propane is C3H8(g) + 5O2(g) +3CO2(g) + 4H2O(g) Which statement is correct about the complete combustion of 3.00 mole of propane, C3Hg ? ► View Available Hint(s) O 3.00 mol CO2 are produced. O 12.00 mol H2O are produced. O 3.00 g CO2 are produced. O 12.00 g H2O are produced. Submit
Propane (C3H8) burns in oxygen to produce carbon dioxide and water via the following reaction: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 49.9 g of propane and sufficient oxygen has a 60.0 % yield.
The combustion of propane may be described by the chemical equation C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g) How many grams of O2(g) are needed to completely burn 70.9 g C3H8(g)? mass O2: g O2
7. Propane is burned in air according to the chemical equation: C3H8(g) + 5 O2(g) ® 3 CO2(g) + 4 H2O(g) If you burn 455g of propane in air, a. How many moles of oxygen is required? ____________________ b. How many moles of CO2 would be produced? ____________________ c. How many moles of H2O would be produced?____________________ d. Why aren't the moles of CO2 and H2O not the same?
The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) C3H8 (g)= -104.7 CO2(g)= −393.5 H2O(g)= −241.8 Calculate the enthalpy for the combustion of 1 mole of propane.
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Consider the combustion of propane: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O(l) ΔH = –2221 kJ Assume that all of the heat comes from the combustion of propane. Calculate ΔH in which 5.00 g of propane is burned in excess oxygen at constant pressure.
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