Question

A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path...

A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 2.45 times that due to gravity?

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Answer #1

a = 2.45*g

= 2.45*9.8 m/s^2

= 24.01 m/s^2

= v^2/r = r*ω^2

so ω = sqrt(a/r) = sqrt(24.01/8.00) = 1.732 rad/s

= 1.732*60/2pi rev/min

= 16.54 rev/min

Kindly rate :)

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