Calculate the mass, in grams, of MgI2 required to prepare exactly 250 mL of a 0.140-M solution of MgI2.
g
No of moles = molarity x volume
No of moles = 0.14 x 0.25
=0.035 moles of MgI2
mass of magnesium iodide = 0.035 x molar mass
= 0.035 x 278 = 9.73 g
Calculate the mass, in grams, of MgI2 required to prepare exactly 250 mL of a 0.140-M...
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