If 25% is given it is the frequency of the recessive genotype(q^{2} = 25/100 = 0.25) The frequency of recessive allele can be calculated as
q = √.25 = 0.5 p= 1- 0.5 = 0.5
Let us assume a population of 200 people in which p= 0.5 and q = 0.5
According to Hardy Weinberg equation, genotype frequency can be calculated from allele frequency by using the equation
p^{2} +q^{2} +2pq = 1
Where p2 = frequency of homozygous dominant AA = 0.5*0.5 = 0.25
Number of homozygous dominant individuals = 0.25 *200 = 50
q2 = frequency of homozygous recessive aa = 0.5 * 0.5 = 0.25
Number of homozygous recessive individuals = 0.25 * 200 = 50
2pq = frequency of heterozygous Aa= 2*0.5*0.5 = 0.5
Number of heterozygous individual = 0.5 *200 = 100
The allele frequency can be calculated by genotype frequency
p = (2*Number of homozygous dominant individuals + Number of heterozygous individuals)/2* total population
(2*50+100)/2*200 = 200/400 = 0.5
q = (2*Number of homozygous recessive individuals + Number of heterozygous individuals)/2* total population
(2*50+100)/2*200 = 200/400 = 0.5
p+q = 1
(Yes you can say 50% alleles are recessive in the population (0.5 * 100 = 50%), both dominant and recessive alleles have the same frequency in this case 0.5)
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