Question

Read a string then count the number of words in the string. Need to count the number of white spaces that include single blank space ' ', tab \t, new line \n. If a non-white space character is followed by a white space or NULL character then it is a word.

Answer 1

`Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

#include <iostream>
using namespace std;

void removeDupWord(string str,int& count,int &sp,int& ne,int& ta)
{
count=0,sp=0,ne=0,ta=0;
string word = "";
char x;
for (int i=0;i<str.length();i++)
{
x=str[i];
if (x == ' ')
{
sp++;
count++;
word = "";
}
else
{
if(x=='\n')
{
ne++;
}
if(x=='\t')
ta++;
word = word + x;
}
}
count++;
}

// Driver function
int main()
{
int count,sp,ta,ne;
string str = "hana mon tana";
removeDupWord(str,count,sp,ne,ta);
cout<<"Number of words are: "<<count<<endl;
cout<<"Number of spaces are: "<<sp<<endl;
cout<<"Number of new line are: "<<ne<<endl;
cout<<"Number of tab space are: "<<ta<<endl;

return 0;
}

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Thanks.