Question

Let x denote the time taken to run a road race. Suppose x is approximately normally...

Let x denote the time taken to run a road race. Suppose x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in 219 to 236 minutes? Round your answer to four decimal places. P =

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Let x denote the time taken to run a road race. Suppose x is approximately normally...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Let x denote the time taken to run a road race. Suppose x is approximately normally...

    Let x denote the time taken to run a road race. Suppose x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in 221 to 240 minutes? Round your answer to four decimal places.

  • Let x denote the time taken to run a road race. Suppose x is approximately normally...

    Let x denote the time taken to run a road race. Suppose x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in 218 to 242 minutes? Round answer to 4 decimal places.

  • Let x denote the time it takes to run a road race. Suppose x is approximately...

    Let x denote the time it takes to run a road race. Suppose x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in less than 162 minutes? Round your answer to four decimal places.

  • Let x denote the time it takes to run a road race. Suppose x is approximately...

    Let x denote the time it takes to run a road race. Suppose x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in less than 158 minutes? Round answer to 4 decimal places.

  • Chapter 06, Section 6.3, Problem 025b time taken to run a road race. Suppose .x is...

    Chapter 06, Section 6.3, Problem 025b time taken to run a road race. Suppose .x is approximately normally distributed with a mean of 190 minutes and a standard deviation of 21 minutes. If one runner is selected at Let x denote the t random, what is the probability that this runner will complete this road race in 222 to 243 minutes? Round your answer to four decimal places. the tolerance is +/-296 Click if you would like to Show Work...

  • Let x denote the time it takes to run a road race. Suppose x is approximately...

    Let x denote the time it takes to run a road race. Suppose x is approximately normally distributed with a mean of 195 minutes and a standard deviation of 24 minutes. If one runner is selected at random, what is the probability that this runner will complete this road race in less than 187 minutes? Round your answer to four decimal places. Attach File Browse My Computer Browse Dropbox Browse Content Collection QUESTION 5 The GPAs of all students enrolled...

  • LUULIS spend scuoying per week have a distribution skewed to the right with a mean of...

    LUULIS spend scuoying per week have a distribution skewed to the right with a mean of 8.6 hours and a standard deviation of 28 houm Find the probability that the mean time spent studying per week for a random sample of 49 college students would be between 8.2 and 8.9 hours. Round your answer to two decimal places. Attach File Browse My Computer Browse Content Collection Browse Dropbox QUESTION 4 Let x denote the time it takes to run a...

  • 1) Let x be a continuous random variable that is normally distributed with a mean of...

    1) Let x be a continuous random variable that is normally distributed with a mean of 21 and a standard deviation of 7. Find to 4 decimal places the probability that x assumes a value a. between 24 and 30. Probability = b. between 17 and 31. Probability = ------------------------------------------------------------------------------------------------------------------------------------------------------ 2) Let x be a continuous random variable that is normally distributed with a mean of 65 and a standard deviation of 15. Find the probability that x assumes a...

  • Question 7 The mean time taken by all participants to run a road race was found...

    Question 7 The mean time taken by all participants to run a road race was found to be 150 minutes with a standard deviation of 10 minutes. Using Chebyshev's theorem, find the percentage of runners who ran this road race in 120 to 180 minutes. Round your answer to the nearest integer the tolerance is +/-2%

  • The times of the finishers in the New York City 10km run are normally distributed with mean of  minutes and st...

    The times of the finishers in the New York City 10km run are normally distributed with mean of  minutes and standard deviation  minutes. It is known that 70% of finishers have a finish time greater than 60 minutes. Let  denote the finishing time for finishers in this race. Find the standard deviation of the finishing time (). The times of the finishers in the New York City 10km run are normally distributed with mean of 61 minutes and standard deviation o minutes. It...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT