Given the reactions,
X(s)+12O2(g)⟶XO(s)Δ?=−983.5 kJX(s)+12O2(g)⟶XO(s)ΔH=−983.5 kJ
XCO3(s)⟶XO(s)+CO2(g)Δ?=+253.5 kJXCO3(s)⟶XO(s)+CO2(g)ΔH=+253.5 kJ
what is Δ? for this reaction?
X(s)+12O2(g)+CO2(g)⟶XCO3(s)
On revesrire the equation 3
CO2(g)+XO(s)------>XCO3(s) dH= -253.5 kj--------- A
Add , 1+A
X(s)+12 O2(g)+ CO2(g)------>XCO3(s), dH= -1237 KJ
Note: On reverding the equation, sign of dH value also gets reversed
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