The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 2.2 3.2 2.5 1.6 0.6 4.0 2.3 1.3 3.6 0.3 2.3 3.4
a) Find the sample mean.
x overbar x equals=
(Round to two decimal places as needed.)
(b) Find the sample standard deviation.
s equals=
(Round to two decimal places as needed.)
(c) Construct a
95%
confidence interval for the population mean
muμ.
A
95%
confidence interval for the population mean is left parenthesis nothing comma nothing right parenthesis .,.
(Round to two decimal places as needed.)
Solution :
Using calculator,
(a)
= 27.3 / 12 = 2.28
(b)
s = 1.17
(c)
t
/2,df = 2.201
Margin of error = E = t/2,df
* (s /
n)
= 2.201 * (1.17 /
12)
Margin of error = E = 0.74
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
2.28 - 0.74 <
< 2.28 + 0.74
1.54 <
< 3.02
(1.54 , 3.02)
The grade point averages (GPA) for 12 randomly selected college students are shown on the right....
The grade point averages (GPA) for 1212 randomly selected college students are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 2.52.5 3.33.3 2.92.9 1.91.9 0.80.8 4.04.0 2.42.4 1.41.4 3.73.7 0.40.4 2.12.1 3.43.4 (a) Find the sample mean. x overbarxequals=nothing (Round to two decimal places as needed.) (b) Find the sample standard deviation. sequals=nothing (Round to two decimal places as needed.)(c) Construct a 9999% confidence interval for the population mean muμ. A 9999%...
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The grade point averages (GPA) for 12 randomly selected college
students are shown on the right. Complete parts (a) through (c)
below. Assume the population is normally distributed.
2.1, 3.1, 2.6, 1.5, 0.6, 4.0, 2.1, 1.1, 3.6, 0.5, 2.1, 3.4
construct a 90% confidence interval for the population mean
The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) 2.1 below. 1.5 Assume the population is normally distributed. 2.1...
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6. The grade point averages (GPA) for 15 randomly selected college students are: 3.3 2.6 1.8 0.2 3.1 0.7 2.3 4.0 2.3 2.0 3.1 3.4 13 26 26 Which of the following is the correct confidence interval procedure for a 95% confidence level? A. SRS Normal told so o known * = 6.25 o=8.52 n= 15 95% CI Zinterval At the 95% confidence level, u is in (1.94, 10.565) B. SRS Normal by QQ graph * = 6.25 s=8.52 n=...
need answer not formulas
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his Question: 1 pt 10 of 20 (0 complete) This Test: 20 The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below Assume the population is noemaly distributed 3.4 0.9 1.3 2.3 2.7 5 4.0 3.8 3.4 1.9 2.4 0.3 (a) Find the sample mean xs[](Round to two decimal places as. needed.) b) Find the sample standard deviation Round to twro...
Consider the data to the right from two independent samples. Construct a 90 % confidence interval to estimate the difference in population means.Click here to view page 1 of the standard normal table. LOADING... Click here to view page 2 of the standard normal table. LOADING... x overbar 1 equals 43 x overbar 2 equals 51 sigma 1 equals 10 sigma 2 equals 14 n 1 equals 35 n 2 equals 40 The confidence interval is left parenthesis nothing comma...
(a) Find the sample mean
(b) Find the sample standard deviation
(c) Construct a 99% confidence interval for the population mean
μ.
The numbers to the right are 2.4, 1.6, 2.3, 0.4, 3.4, 0.9, 1.1,
2.3, 2.6, 4.0, 3.8, 3.2
6.2.26-T Question Help The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below. 2.4 3.4 2.6 1.6 0.9 4.0 Assume the population is normally distributed. 2.3 1.1 3,8...