Can someone show me how to calculate liters at 800 bar?
Fort Collins, CO 
Calculation 
Result 

Moles of H_{2} for your community 
(8.952e^{4} moles H_{2}/day)(5 days) 
0.004476 moles H_{2}[NH5] 

Liters of H_{2} for your community at STP 
(4.476e^{3}mol H_{2})/1X(22.4L)/1mol H_{2}= 
.106624 L 

Liters of H_{2} for your community at 800 bar 

Number of railroad tanker cars to hold your compressed H_{2} 
You should know that at STP (1 bar, 273K) the volume of 1 mole gas is equal to 22.4 liters.
Here given liters of H_{2} at 22.4^{0} C =0.106624 liters, then 0.004476 moles occupy 0.106624*0.004476 liters = 0.000477 liters.
Now apllying Boyle's law;
P_{1} V_{1} = P_{2} V_{2}
P_{1}= 1 bar (STP)
P_{2}= 800 bar (given)
V_{1} =0.000477 liters
So V_{2}= (P_{1} * V_{1})/ P_{2}
V_{2} = (1 * 0.000477)/800
V_{2} = 5.96 * 10^{7} liters.
Can someone show me how to calculate liters at 800 bar? Fort Collins, CO Calculation Result...
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