Question

For a 1st order reaction the logarithm of concentration is linear to time. The linear equation...

For a 1st order reaction the logarithm of concentration is linear to time. The linear equation of the following curve is lnC = lnC0 – 0.2t; where C is the molar concentration (M) of a reactant, C0 is the molar concentration at time t = 0 (the starting concentration or the initial concentration), and in this particular case C0 = 10 M; and t is time in seconds. What is the slope (and the unit) of the curve? What will be molar concentration of the reactant at time t = 40 sec?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

Given linear equation for first order reaction is

lnC=lnC0 - (0.2)t

Or lnC=-(0.2)t + lnC0

y=mx+C

[lnC=-kt + lnC0]

Therefore the plot lnC vs time gives slope=-0.2 s^-1=-k

Here k=rate constant=0.2 s^-1.

Given C0=10M, C=? at t=40s.

Therefore lnC=-(0.2s^-1)(40s) + ln10

lnC=-5.697

C=e^-5.697=3.35x10^-3 M

Therefore molar concentration of reactant at t=40s is

C=3.35x10^-3 M.

Please let me know if you have any doubt. Thanks.

Add a comment
Know the answer?
Add Answer to:
For a 1st order reaction the logarithm of concentration is linear to time. The linear equation...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT