How hot would a source need to be to emit its maximum radiation in the FM...
How hot would a source need to be to emit its maximum radiation in the FM range of the radio dial (105.8 MHz)? Why do common objects not interfere with our radio reception?
Homework Answers
f = frequency = 105.8 x 106 Hz
c = speed of radiation = 3 x 108 m/s
Wavelength of the radiation is given as
= c/f
= (3 x
108)/(105.8 x 106)
= 2.84 m
Temperature of radiation is given as
T = b/
T = 2.898 x 10-3 /2.84
T = 0.00102 K = 1.02 x 10-3 K
common objects do not inteference because the wavelength is large and not comparable with the wavelength of the objects.
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