Consider the following elementary step
X + 2Y
→
XY2
If the initial rate of formation of XY2 is 0.0026
M/s and the initial concentrations of X and Y are 0.66
Mand 0.76 M, what is the rate constant for the
reaction?
Answer will be in M^-2s^-1
Thank you
Given reaction is the form of
X + 2 Y --> XY2
Rate of the reaction is the speed at which the reactants is converted to products.
So Rate of Reaction is given by:
Rate = k [X] [Y]^2, where k is the rate constant.
Here, Rate = 0.0026 M/s
[X] = 0.66 M
[ Y ] = 0.76 M
So k = Rate/ [ X] [Y]^2
k = 0.0026/ 0.66* (0.76) ^ 2
= 0.0022754 M^-2 s^ -1.. . Answer
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