Question

A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate....

A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate. Calculate the pH of the solution following the addition of 0.066 moles of NaOH. Assume that any contribution of the NaOH to the volume of the solution is negligible. The Ka of butanoic acid is 1.52 × 10-5.

A 1.44 L buffer solution consists of 0.326 M propanoic acid and 0.103 M sodium propanoate. Calculate the pH of the solution following the addition of 0.062 moles of HCl. Assume that any contribution of the HCl to the volume of the solution is negligible. The Ka of propanoic acid is 1.34 × 10-5.

A buffer with a pH of 4.38 contains 0.27 M of sodium benzoate and 0.18 M of benzoic acid. What is the concentration of [H ] in the solution after the addition of 0.054 mol of HCl to a final volume of 1.4 L? Assume that any contribution of HCl to the volume is negligible.

Buffer capacity is a measure of a buffer solution\'s resistance to changes in pH as strong acid or base is added. Suppose that you have 185 mL of a buffer that is 0.140 M in both propanoic acid (C2H5COOH) and its conjugate base (C2H5COO–). Calculate the maximum volume of 0.190 M HCl that can be added to the buffer before its buffering capacity is lost.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT