ZuoTi.Pro
Question

You can infer that only 2.28% of all the girls who took this test got a...

You can infer that only 2.28% of all the girls who took this test got a score below…

150
120
90
60
math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer

The mean score for girls was 150,

with a standard deviation of 30.

Only 2.28% of all the girls who took this test got a score below : ?

Lets see the Z-score of 2.28%, it is -2.00

So, the score of the person should be -2 deviation from the mean. = -2*30 + 150 = 90

Hence, answer is 90

0 0
Add a comment
Know the answer?
Add Answer to:
You can infer that only 2.28% of all the girls who took this test got a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Three potential employees took an aptitude test. Each person took a different version of the test....

    Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below. Kaitlyn got a score of 79.7 ; this version has a mean of 73.7 and a standard deviation of 12 . Pierce got a score of 237.2 ; this version has a mean of 227 and a standard deviation of 17 . Norma got a score of 8.7 ; this version has a mean of 6.7 and a standard...

  • Nine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between...

    Nine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between 0 (0%) and 10 (100%). Their scores are listed below. Student   Raw Score A 4 B 5 C *5* D 6 E 6 F 6 G 7 H 7 I 8 The class mean is 6, median is 6 , mode is 6 , range is 4 , and standard deviation is 1.1(round to one decimal place). Look at Student C's score. The score...

  • We want to know whether boys or girls get into trouble more often in school. Below...

    We want to know whether boys or girls get into trouble more often in school. Below is the table documenting the percentage of boys and girls who got int Gender Got in Trouble No Trouble Total Boys 43 71 117 Girls 37 83 120 Total 83 154 237 Examine statistically whether boys got in trouble in school more often. Can you create a StatCrunch crosstabulation table result for this data? Perform the chi-square analysis. Make sure to state the five...

  • ine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between...

    ine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between 0 (0%) and 10 (100%). Their scores are listed below. Student   Raw Score A 4 B 5 C *5* D 6 E 6 F 6 G 7 H 7 I 8 The class mean is 6, median is 6 , mode is 6 , range is 4 , and standard deviation is 1.1(round to one decimal place). Look at Student C's score. The score...

  • Nine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between...

    Nine students in Mr. Ruiz's class all took a spelling test. Raw scores can range between 0 (0%) and 10 (100%). Their scores are listed below. Student   Raw Score A 4 B 5 C *5* D 6 E 6 F 6 G 7 H 7 I 8 The class mean is 6, median is 6 , mode is 6 , range is 4 , and standard deviation is 1.1(round to one decimal place). Look at Student C's score. The score...

  • A new exam was written to be used as an entrance exam. You took the exam...

    A new exam was written to be used as an entrance exam. You took the exam and your score report said that you got a score of 633 points out of 800 possible and that the mean and standard deviation for all test takers is μ = 400 and σ = 100 and the distribution is normal. What percentage of students taking the test scored higher than you did? The department decides to accept all the students who score in...

  • You want to estimate the average GMAT score for all students who took the Logitano GMAT...

    You want to estimate the average GMAT score for all students who took the Logitano GMAT Preparation course during the past 2 years. You select a random sample of 100 such students from a comprehensive list of all students who took the course over the last two years and find that the average GMAT score for the sample was 1040. Suppose now you build a 95% confidence interval estimate of the average score for the population of Logitano students represented...

  • In a city with three high schools, all the ninth graders took a Standardized Test, with...

    In a city with three high schools, all the ninth graders took a Standardized Test, with these results: High School Mean score on test Number of ninth graders Glenwood 79 273 Central City 94 330 Lincoln High 73 174 The city's PR manager, who never took statistics, claimed the mean score of all ninth graders in the city was 82 . Of course, that is incorrect. What is the mean score for all ninth graders in the city? Round to...

  • in a city with three high schools, all the ninth graders took a Standardized Test, with...

    in a city with three high schools, all the ninth graders took a Standardized Test, with these results High School Mean score on test Number of ninth graders lons 10.417 2.10021 132/21 250223 Central City Lincoln High The city's PR manager, who never took Statistics, comed the mean score of all ninth graders in the city was 80 J. Of course that is incorrect. What is the mean score for all ninth graders in the city? Round to one decimal...

  • Bill Board is “lording” his SAT score over his friend, Rhoda Dendron, who took the ACT....

    Bill Board is “lording” his SAT score over his friend, Rhoda Dendron, who took the ACT. “You only got a 25 in math,” he chortled, “while I got a 300 in math.” Given that the SAT has a μ of 500 and a σ of 100, and the ACT has a μ of 20 and a σ of 5, what is wrong with Bill’s logic (give the answer in both z scores and percentile ranks).

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT